Involute gear designs calculated description

6 working hours: 50000 hours one, helical gear of standard of affirmatory gear type, gear cooperates drive of the clench the teeth outside be. 2, choice material pinion: 50SiMn, shift is simple, 255 gear of HB=207 ～ : 42SiMn, shift is simple, 255 basises of HB=196 ～ pursue 2.

5-14(a) and graph 2.

5-43(a) , take σ Hlim1=1350 MPa, σ Hlim2=1350 MPa, σ Flim1=360 MPa, σ Flim2=360 MPa. Rz1=3 of tooth flank surface roughness.

M of 2 μ , rz2=3.

M of 2 μ , m of μ of Rz1=10 of surface roughness of tine root surface, m of Rz2=10 μ . Big, pinion designs M of μ of Ca1=30 of the quantity that build a predestined relationship, m of Ca2=30 μ . Oil bath is lubricant, ν 50=20 Mm^2/s, agglutination carrying capacity is FZG7 class. 3, preliminary and affirmatory main parameter 1.

By osculatory intensity preliminary and affirmatory center is apart from A (the basis is expressed 2.

5-1) coefficient Aa: 12 ° of ～ of =8 of helix angle β , the basis is expressed 2.

5-2, k of coefficient of load of deputy to the gear of steel to steel Aa=476: Take A of φ of K=2 facewidth coefficient: The basis is expressed 2.

5-4, φ A=0.

The nominal torsion of 5 pinion: M of T1=9549*P/n1=2717 N · is allowable contact stress: Hlim1 of σ Hlim=min{σ , HP=0 of σ of σ Hlim2}=1350 MPa.

9* σ Hlim=1215.

00MPa computation: ≥ of HP^2)]^(1/3) of б of A=Aa*(u+1)*[(K*T1)/(Φ A*u* 205.

83 Mm circle is full for A=250 Mm. 2.

Basis of number of preliminary and affirmatory modulus, tine, helix angle is expressed 2.

1-1, take modulus M=3.

5 Mm by the watch 2.

The formula of 2-1 can derive β of 1=2acos of Ζ of ° of =12 of primary election β / [M*(u+1)]=53.

74 1=54 extraction Ζ , 1=86 of Ζ 2=u* Ζ .

40, take Ζ 2=87. After 2 classics circle rectifies Ζ , gear ratio produced change, number of actual teeth compares 1=1 of Ζ of 2/ of the Ζ that it is U= .

611. Essence of life calculates β =arccos[m*(Ζ 14 ′ of 2+ Ζ 1)/2a]=9 ° 55 ″ 4, the computation of other geometry parameter (the basis is expressed 2.

2-1) 1.

Reference circle pressure angle 00 ′ of α N=20 ° 00 ″ 2.

=13 of ˇ of Han of coefficient of height of teeth top.

Carry =0 of ˇ of Cn of unoccupied place coefficient on the head.

254.

Facewidth B1=140 Mm, b2=140 Mm5.

1=1 of Ζ of 2/ of Ζ of gear ratio U= .

6116.

=191 of β of Ζ 1/cos of D1=mn* of reference circle diameter.

=308 of β of 2/cos of Ζ of 489 Mm D2=mn* .

511 Mm7.

β of N/cos of α of T=arctan(tan of α of basic circle diameter) 14 ′ of =20 ° T=179 of α of 32 ″ Db1=d1*cos.

T=289 of α of 662 Mm Db2=d2*cos.

457 Mm8.

*mn=3 of ˇ of Ha1=ha2=han of height of teeth top.

500 Mm9.

ˇ of Hf1=hf2=(han of height of teeth root + Cn ˇ ) *mn=4.

375 Mm10.

H1=h2=ha1+hf1=ha2+hf2=7 of fully teeth height.

875 Mm11.

Tine carries round diameter Da1=d1+2*ha1=198 on the head.

489 Mm Da2=d2+2*ha2=315.

511 Mm12.

Df1=d1-2*hf1=182 of tine root round diameter.

739 Mm Df2=d2-2*hf2=299.

761 Mm13.

Tine carries ° of At1=arccos(db1/da1)=25 of pressure angle α on the head 24 ″ of 9 ′ 26 ′ of α At2=arccos(db2/da2)=23 ° 52 ″ 14.

End panel registration =1 of π of T)]/2 of ′ of α of At2-tan of α of 2(tan of Ζ of T)+ of ′ of α of At1-tan of α of 1(tan of Ζ of =[of α of ε of T of α of α ′ T= .

76715.

Axial registration ε β =b*sin β / (π *mn)=2.

046 (B=min{b1, b2} ) 16.

Gross weight adds up to α of ε of = of the γ that spend ε + ε β =3.

81317.

β of β B^2*cos of 1/(cos of Ζ of V1= of Ζ of equivalent tine number) =55.

β of β B^2*cos of 2/(cos of Ζ of V2= of 988 Ζ ) =90.

203 CNC Milling CNC Machining